56-2x^2=24x

Solution for 56-2x^2=24x equation:

56-2x^2=24x

We move all terms to the left:

56-2x^2-(24x)=0

a = -2; b = -24; c = +56;
Δ = b2-4ac
Δ = -242-4·(-2)·56
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-32}{2*-2}=\frac{-8}{-4}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+32}{2*-2}=\frac{56}{-4}
=-14
$